Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then sum of the digits in N is = ?

Question

0

Mathematics

asked Sep 07, 2023 at 09:12

A

Sign in to add a comment

Answer 1

0

N = HCF of (4665 - 1305) (6905 - 4665) and (6905 - 1305) = HCF of 3360, 2240 and 5600 = 1120 Sum of digits in N = (1 + 1 + 2 + 0) = 4

answered Sep 07, 2023 at 09:12

A

Answer 2

N = HCF of (4665 - 1305) (6905 - 4665) and (6905 - 1305) = HCF of 3360, 2240 and 5600 = 1120 Sum of digits in N = (1 + 1 + 2 + 0) = 4

Your Answer