The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

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Mathematics

asked Sep 07, 2023 at 09:12

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Answer 1

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Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 = 127

answered Sep 07, 2023 at 09:12

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Answer 2

Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 = 127

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