The LCM of two numbers is 48. The numbers are in the ratio of 2 : 3. Find the sum of the numbers.

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Mathematics

asked Sep 07, 2023 at 09:12

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Answer 1

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Let numbers are 2N and 3N. According to the question, 6N = 48 ⇒ N = 8 ( ∵ LCM = 6N ) ∴ Required sum = ( 2N + 3N ) = 5N = 5 x 8 = 40

answered Sep 07, 2023 at 09:12

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Answer 2

Let numbers are 2N and 3N. According to the question, 6N = 48 ⇒ N = 8 ( ∵ LCM = 6N ) ∴ Required sum = ( 2N + 3N ) = 5N = 5 x 8 = 40

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