The sum of all two digit numbers divisible by 5 is

Asked Sep 07, 2023 Modified Sep 07, 2023 Viewed 0 times
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asked Sep 07, 2023 at 09:12
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Required numbers are 10,15,20,25,...,95 This is an A.P. in which a=10,d=5 and l=95. Let the number of terms in it be n.Then t=95 So a+(n-1)d=95. 10+(n-1)*5=95,then n=18. Required sum=n/2(a+l)=18/2(10+95)=945.
answered Sep 07, 2023 at 09:12

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