Account

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

Asked Sep 07, 2023 Modified Sep 07, 2023 Viewed 0 times

Mathematics

asked Sep 07, 2023 at 09:12

1 Answer

Here, S = {1, 2, 3, 4, ...., 19, 20}. Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}. P(E) = n(E)/n(S) = 9/20.

answered Sep 07, 2023 at 09:12

Your Answer