What is the greatest number that divides 263, 935 and 1383 leaving a remainder of 7 in each case ?

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Mathematics

asked Sep 07, 2023 at 09:12

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Answer 1

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The required greatest number is the HCF of 263-7, 935-7, 1383-7 i.e. 256, 928 and 1376 HCF = 32

answered Sep 07, 2023 at 09:12

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Answer 2

The required greatest number is the HCF of 263-7, 935-7, 1383-7 i.e. 256, 928 and 1376 HCF = 32

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