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Electric Field due to an Isolated Point Charge #8211; Electric field at a distance r from a source change q is given by E = 1/4πε<sub>0</sub> q/r<sub>2</sub> For a positive charge (+q), vector E is directed radially outwards from it and for a negative charge (-q), vector E is directed radially inwards. Electric field due to a system of charges : Superposition of electric fields. The magnitude of the resultant of two electric fields is given by (E = E<sup>2</sup><sub>1</sub> + E<sup>2</sup><sub>2</sub> + 2E<sub>1</sub> E<sub>2</sub> cosθ and its direction is given by [tanα = E<sub>2</sub> sinθ/E<sub>1</sub> + E<sub>2</sub> cosθ]
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