1
Electric Field due to Charged Conducting Sphere #8211; If a charge on a conducting sphere of radius R is Q and σ is surface charge density as shown in the figure below, then electric field in different situations are (i) Outside the sphere #8211; If point p lies outside the sphere, E<sub>out</sub> = 1/4πε<sub>0</sub>times;Q/r<sup>2</sup> = σR<sup>2</sup>/ε,subgt;0</sub> r<sup>2</sup> [∵ Q = σ times; A] (ii) At the surface of sphere #8211; At surface, r = R So, E<sub>s</sub> = 1/4πε<sub>0</sub> times; Q/R<sup>2</sup> = σ/ε<sub>0</sub> (iii) Inside the sphere #8211; Inside the conducting change sphere, electric field is zero. E<sub>in</sub> = 0
New Questions
New Blog Post
Network Questions