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Inductance of a Solenoid #8211; The magnetic flux through each turn is, Փ<sub>B</sub> = BS = μ<sub>0</sub> NS/l times;I Here, S is the cross-sectional area of the solenoid. Now, n = N/l is the number of turns per unit length L = Nɸ<sub>B</sub>/I = N/I(μ<sub>0</sub> NSI/l) ⇒ [L = μ<sub>0</sub> N<sup>2</sup>S/l]
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