• 10

  • 46

  • 70

  • 90


LCM = 495 HCF = 5 ( given ) тИ┤ Let numbers are = 5x and 5y тИ┤ LCM = 5xy тЗТ 5xy = 495 тЗТ xy = 99 тИ┤ Possible co-prime factors are 1, 99 9, 11 тИ┤ Possible numbers are 5x, 5y 45, 55 5, 495 Now given that sum of numbers = 100 So, required numbers are = (45, 55) тИ┤ Difference of numbers = 55 - 45 = 10

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