LCM = 495
HCF = 5 ( given )
тИ┤ Let numbers are = 5x and 5y
тИ┤ LCM = 5xy
тЗТ 5xy = 495
тЗТ xy = 99
тИ┤ Possible co-prime factors are
1, 99
9, 11
тИ┤ Possible numbers are 5x, 5y
45, 55
5, 495
Now given that sum of numbers = 100
So, required numbers are = (45, 55)
тИ┤ Difference of numbers = 55 - 45 = 10
Answered :- 2023-09-07 09:12:33
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