476 ** 0 is divisible by both 3 and 11.The non zero digits in the hundreds and tens places are respectively

Let the number be 476ab0 476ab0 is divisible by 3 => 4 + 7 + 6 + a + b + 0 is divisible by 3 => 17 + a + b is divisible by 3 ------------------------(i) 476ab0 is divisible by 11 [(4 + 6 + b) -(7 + a + 0)] is 0 or divisible by 11 => [3 + (b - a)] is 0 or divisible by 11 --------------(ii) Substitute the values of a and b with the values given in the choices and select the values which satisfies both Equation 1 and Equation 2. if a=6 and b=2, 17 + a + b = 17 + 6 + 2 = 25 which is not divisible by 3 --- Does not meet equation(i).Hence this is not the answer if a=8 and b=2, 17 + a + b = 17 + 8 + 2 = 27 which is divisible by 3 --- Meet equation(i) [3 + (b - a)] = [3 + (2 - 8)] = -3 which is neither 0 nor divisible by 11---Does not meet equation(ii).Hence this is not the answer if a=6 and b=5, 17 + a + b = 17 + 6 + 5 = 28 which is not divisible by 3 --- Does not meet equation (i) .Hence this is not the answer if a=8 and b=5, 17 + a + b = 17 + 8 + 5 = 30 which is divisible by 3 --- Meet equation 1 [3 + (b - a)] = [3 + (5 - 8)] = 0 ---Meet equation 2 Since these values satisfies both equation 1 and equation 2, this is the answer