• 28

  • 32

  • 40

  • 64


Let numbers are 2N and 3N. According to the question, 6N = 48 тЗТ N = 8 ( тИ╡ LCM = 6N ) тИ┤ Required sum = ( 2N + 3N ) = 5N = 5 x 8 = 40

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